By A. M. P. Brookes and P. Hammond (Auth.)
Read Online or Download Advanced Electric Circuits PDF
Best construction books
- Advanced paper aicraft construction
- 17th Edition IET Wiring Regulations: Wiring Systems and Fault Finding for Installation Electricians, 6th ed
- Guidance Note 7: Special Locations (IEE Guidence Notes) (IEE Wiring Regulations) (No 7)
- The Construction and Operation of Clandestine Drug Laboratories (2nd ed: 85178)
- Three Tellings, Four Models and Differing Perceptions: The Construction of Female Sexuality in the Ramayana
- Construction Creativity Casebook
Additional resources for Advanced Electric Circuits
Applied to the bridge is necessary and nonlinear relationship between the parameter being measured and the voltage or current in the detector is of no account. We are not concerned here with the design of bridge circuits, of which there are many, but with the analysis of the circuit and the determination of the balance conditions. The methods of obtaining these are best shown by worked examples. 35 36 ADVANCED ELECTRIC CIRCUITS Example 1. By the use of Thevenin's theorem, or otherwise, derive an exact expression for the current flowing through the galvanometer in the circuit shown in Fig.
3. FIG. 3 Ans: CiRi = C2R3; L = C2R2R3 4. c. bridge shown in Fig. 4. FIG. 4 Ans: R1R4 =-- R2R3 = L/C 50 ADVANCED ELECTRIC CIRCUITS 5. c. bridge shown in Fig. 5. FIG. c. bridge networks discussed in the previous chapter are tuned. Similarly an electrical filter is a network which offers less impedance to currents of certain frequencies than to those at other frequencies and so a filter is also a tuned network. The relationship between any chosen parameters for the network is known as its response curve or characteristic and it is usually the aim of the designer of a network to achieve a characteristic as close to an ideal one as is possible with reasonable economy.
Between A and B would be (Fig. (b)): Remembering that the internal resistance of the cell is zero, the resistance between the points A and B, with the galvanometer removed, can be determined by re-drawing the circuit as in Fig. 1(c). The resistance is thus equal to R_ R(R + 8R) RJ4R + 38R) 2+ 2R + 8R ~~ 4R + 28R Hence, by Thevenin's theorem, the current through the galvanometer is given by . = / E8R \ (4R* + ~\4R + 28R) \ l = 3R8R+4R6+268R\ 4R + 28R ) E8R R(4R + 38R) + 6(4R + 28R) When 8R is small compared with R then i is proportional to 8R.